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Tool Talk Discussion Forum

Engineering problem.

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steve from mo -

08-17-2006 06:27:19

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When you hang a weight in the center of a cable that"s fastened on the ends, you create a tension on the cable that"s more than if you hang the weight from the end of the cable. I"m sure there"s someone that"s an engineer who can give you approximate values for this, but I can"t.

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swms301

08-17-2006 11:15:33

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Re: Engineering problem. in reply to steve from mo - dangit!, 08-17-2006 06:27:19

From my rigging chart on the wall. Take the distance from the weight to the pont it connects to the wall, divide by the vertical distance the weight sags the cable, then multiply the weight. Example: if the total length of the cable between connecting points is 6' long and the weight is 4000# (and centered on the cable)and it hangs down 1' from horizontal then the tension is 3'/1' times 4000# or 12000#.

This should also work if the load is not centered on the cable. To figure the tension take the distance along the cable from the load to the connection point, divide by how far down the weight is to the connection point and multiply time the weight of the load.

That should work. But dont stand under the load, in case my chart is wrong.

Good Luck.

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steve from mo - dangit!

08-17-2006 11:23:37

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Calvin's Dad said this: in reply to swms301, 08-17-2006 11:15:33

They drive heavier and heavier trucks over the bridge until it collapses. Then they weigh that truck, rebuild the bridge, and post that weight on the sign.

Ought to work for a tree fort as well.

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John T

08-17-2006 18:22:27

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Re: Calvin's Dad said this: in reply to steve from mo - dangit!, 08-17-2006 11:23:37

Thas kinda like when I need a bolt or nut real good n tight I tell my son to turn it but stop just 1/4 turn BEFORE it would snap off n break lol

John T

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Stan in Oly, WA

08-17-2006 15:55:34

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Re: Calvin's Dad said this: in reply to steve from mo - dangit!, 08-17-2006 11:23:37

Hi Steve,

That's kind of like how the Soviet political officer would calculate the number of soldiers it would take to make a successful frontal assault on a German position in War II: Number of German machine guns times cyclic rate in bullets per minute times minutes to cross the open ground. Add 25% to do the actual fighting and it's virtually a done deal. Nothing to it. Hard on the troops, though.

That's horrible, isn't it?

Stan

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