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Tool Talk Discussion Forum

Help save my floating tree fort

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Jerry in MI

08-16-2006 20:23:20

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This is a tractor site, but everyone has been helpful on a lot of stuff.All the tree house sites I've checked don't show discussion boards, your two cents please.
I have an 8ft by 10ft platform framed in. The main point of connection with a huge Oak is a gate hinge strap bolted to an 8x10, on a gate pin screwed into the tree. It is 3ft in from the corner of the 10foot back side.
I have 2 Basswood trees near on this treeline. I was planning to use telephone company cable (7wire 3/16) to connect at each end of a 1 1/2 inch pipe running underneath 16inches from the front side.
One up to the Oak's limb at 70-80 degrees from the frame. The other end up to a Bass wood at 45 degrees or less severe as cable permits.
My current hinge point leaves it off the center of balance, (but I can't come up with a way to move the trees).
Part of me just wants 4x4's under the corners and call it a day, but the kid (in me) envisions a floating platform which will cause people to do a double take when they first look.
Can I run diagonal cable stringers underneath to obtain and hold level the platform?
Am I over the weight load on the cable performance? Concerns for snow load this winter?
Concerns for safety or back up for this set up?
Thanks for your time.

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VADAVE

08-17-2006 07:16:40

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Re: Help save my floating tree fort in reply to Jerry in MI, 08-16-2006 20:23:20

Little off topic. You do know that oak trees have value and that pins driven into them will stain the wood the full elngth of the tree. Thus lowering the value.

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steve from mo - dangit!

08-17-2006 06:27:19

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Engineering problem. in reply to Jerry in MI, 08-16-2006 20:23:20

When you hang a weight in the center of a cable that"s fastened on the ends, you create a tension on the cable that"s more than if you hang the weight from the end of the cable. I"m sure there"s someone that"s an engineer who can give you approximate values for this, but I can"t.

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swms301

08-17-2006 11:15:33

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Re: Engineering problem. in reply to steve from mo - dangit!, 08-17-2006 06:27:19

From my rigging chart on the wall. Take the distance from the weight to the pont it connects to the wall, divide by the vertical distance the weight sags the cable, then multiply the weight. Example: if the total length of the cable between connecting points is 6' long and the weight is 4000# (and centered on the cable)and it hangs down 1' from horizontal then the tension is 3'/1' times 4000# or 12000#.

This should also work if the load is not centered on the cable. To figure the tension take the distance along the cable from the load to the connection point, divide by how far down the weight is to the connection point and multiply time the weight of the load.

That should work. But dont stand under the load, in case my chart is wrong.

Good Luck.

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steve from mo - dangit!

08-17-2006 11:23:37

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Calvin's Dad said this: in reply to swms301, 08-17-2006 11:15:33

They drive heavier and heavier trucks over the bridge until it collapses. Then they weigh that truck, rebuild the bridge, and post that weight on the sign.

Ought to work for a tree fort as well.

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John T

08-17-2006 18:22:27

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Re: Calvin's Dad said this: in reply to steve from mo - dangit!, 08-17-2006 11:23:37

Thas kinda like when I need a bolt or nut real good n tight I tell my son to turn it but stop just 1/4 turn BEFORE it would snap off n break lol

John T

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Stan in Oly, WA

08-17-2006 15:55:34

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Re: Calvin's Dad said this: in reply to steve from mo - dangit!, 08-17-2006 11:23:37

Hi Steve,

That's kind of like how the Soviet political officer would calculate the number of soldiers it would take to make a successful frontal assault on a German position in War II: Number of German machine guns times cyclic rate in bullets per minute times minutes to cross the open ground. Add 25% to do the actual fighting and it's virtually a done deal. Nothing to it. Hard on the troops, though.

That's horrible, isn't it?

Stan

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