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Re: Re: O/T for you science buffs


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Posted by Rod F. on November 09, 2003 at 17:10:12 from (142.177.112.63):

In Reply to: Re: O/T for you science buffs posted by IT CAN BE DONE on November 09, 2003 at 10:17:16:

Well, well. This has been an interesting discussion. You put a lot of time into this one. I won't argue the numbers you put up, but still wonder about some of it. But since you asked about flaws in your theory below, I'll take a shot, so to speak. First, I don't see why muzzle velocity is important, and I am confused about "torque". So, as I think of this in purely theoretical terms, and for a moment, I will ignore all forces at work except gravity. We have a bullet in the gun, we point it straight up, and fire. Now, the force of the explosion and expansion force the bullet away, it increases in velocity, and should reach Vmax as it clears the barrel. Correct? Now, this is where I do not see what role torque plays. That to me seems to be a linear force. Also, at this point I assume that the bullet becomes a simple projectile or glider, as it no longer receives any energy from the explosion. We also know that gravity alone will exert force in a manner that will cause an acceleration of 32 feet/sec. So, that in theory should also cause a deceleration of 32 feet/sec. So, the bullet will rise in the vertical plane, decelerating at a rate of 32 feet/sec as gravity slows it down, stops in mid air, and then begins to fall, now accelerating at a rate of 32 feet/sec reaching Vmax at the point of begining, assuming that to be the end of the barrel. Vmax should be the same when the bullet returns as when it left. So, the way I see it, purely in a theoretical sense, is that Vmax is not a relevant number, whether it is 100 feet/second or 1000 feet/second. This being true, the size of the charge would affect Vmax, which would determine the distance traveled, but the bullet would have the same velocity at any given point in it's travel, without reguard for it's direction of travel. And I truly don't understand where torque figures into this. Not trying to flame you here, just curious.

Rod


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