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Re: injector pump timing/running 180* out?


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Posted by jdemaris on October 06, 2014 at 05:11:32 from (70.194.15.19):

In Reply to: injector pump timing/running 180* out? posted by mite-help on October 05, 2014 at 13:54:50:

Define 180 degrees out of time. Rotary injection pump on a John Deere runs at only half engine speed. If you flip it over 180 degrees it does not get 180 degrees out of time. That puts it 90 degrees out of time.

If you truly found a way to install the injection pump 180 degrees out of time - that would have the pump firing on the exhaust stroke of every cylinder. If youjust flipped the half-speed pump over and put it 90 degrees out of time - but somehow found a way to hook the correct lines to the same correct discharge ports (not really possible) - every cylinder would inject on the bottom of the power stroke and nothing would fire.

Now .. if you flip the pump over and hook the injector lines to the wrong ports -then I guess it's a crap shoot. Define what you are asking.

A pump upside down (90 degrees off) but with all the lines also reversed - i.e. . . #1 line hooked to #6 port, #5 line hooked to #2 port, #3 line hooked to #4 port, #6 line hooked to #1 port, and #2 line hooked to #5 port?? Seems to me it this would have every cyliner firing on the bottom of its exhaust stroke instead of the top of the compression stroke. Can't see how any cylinders would fire. What am I missing??


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