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Need a Mathematician

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Haywood

09-28-2007 16:34:36

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My Trailer is 18 feet long with 6 foot ramps. The degree of slope for the loading ramps is 21 Degrees and my tractor is a Farmall M W/NF and weighs 5200lbs as equipped.

How much pulling force measured in pounds will it take to pull the Farmall M up the ramps and onto the deck?

What is the formula?

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Jeff-oh

10-01-2007 11:10:32

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Re: Need a Mathematician in reply to Haywood, 09-28-2007 16:34:36

The force needed to pull the tractor is 1900lbs + amount needed to pull flat.

Equation is 5200lbs * sin 21(degrees) this is the force needed to hold the tractor on the ramp. To move the tractor forward the equation is

F= friction factor * Mass = FF * 5200 lbs

A block sliding on a smooth ramp has a FF of .3 However, a wheeled Tractor has a FF much lower. i.e pull the tractor on level ground and that is the force you need to ad.

This all assumes the applied force is in line with the ramp. Though with the low angle of a wench at the front of the trailer it will not be too much more. i.e. less than 25lbs.

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Haywood

10-02-2007 11:06:28

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Re: Need a Mathematician in reply to Jeff-oh, 10-01-2007 11:10:32

Thanks Guys

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Jeff-oh

10-01-2007 11:09:11

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Re: Need a Mathematician in reply to Haywood, 09-28-2007 16:34:36

The force needed to pull the tractor is 1900lbs + amount needed to pull flat.

Equation is 5200lbs * sin 21(degrees) this is the force needed to hold the tractor on the ramp. To move the tractor forward the equation is

F= friction factor * Mass = FF * 5200 lbs

A block sliding on a smooth ramp has a FF of .3 However, a wheeled Tractor has a FF much lower. i.e pull the tractor on level ground and that is the force you need to ad.

This all assumes the applied force is in line with the ramp. Though with the low angle of a wench at the front of the trailer it will not be too much more. i.e. less than 25lbs.

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john_bud

09-28-2007 17:03:12

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Re: Need a Mathematician in reply to Haywood, 09-28-2007 16:34:36

WHat's the height you are raising it up to?

Tractor weight * Bed Height in ft/ramp length in feet

5200#* 1.4 feet /6 = 1213# That'll be close

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