How many tons of force do I "really" need? I started calculating some of these 24 ton and 30 ton log splitters and noticed some errors in the way they come up with the force. My math teacher taught me to figure force, you squared the radius of the cylinder, multiply that by PI, then multiply by the pressure you have. (PI R Square x Pressure) So a 4" cylinder at 2000# would be 2x2=4 x 3.14= 12.57 x 2000 = 25,000 = 12 tons. But they clearly advertise it as a 24 ton splitter??I'm splitting oak and mesquite logs about 3" to 6" in diameter about 18 to 24" long. So will I be satisfied with 10 to 12 actual tons? If I build one, it will be powered from my tractor hydraulics, and the cylinder would push the log over the wedge on the end. This way, all of the split wood would fall into a pile, or trailer. I planned on a simple single wedge. I think I can build one using a new cylinder, valve, and hoses for about $250-$300 using steel and I Beam I have on hand. The store bought 3pt at TSC are about $600 and look a little light, plus they push the wedge and not the wood. Any ideas, advice, or comments? Thanks.
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