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Hydraulic pump motor sizing

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Zira

11-23-2002 16:42:38




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I pulled a hydraulic pump off a Briggs 18 hp (@3600 rpm) motor. I plan to run this with a 9 1/2 Wisconsin that max's out at 2200 rpm. I know the flow rate will be less with the smaller, slower motor but will I be able to get enough pressure for a log splitter with a 4" X 24" piston?

BTW, the pump has no tag or info on it so I do not know whatitsrated GPM is - I am guessing it is over 15 since it was hooked up to an 18hp motor.

Thanks for any/all help.

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taylor lambert

11-28-2002 20:07:07




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 Re: Hydraulic pump motor sizing in reply to Zira, 11-23-2002 16:42:38  
Ive busted many 30 inch oak logs with a 5 horse Briggs and a 2 stage pump. It has a side for hi flow then when it gets in a bind to low side kicks in and pushes the ram on through. on the on the first 2 splitters we put out enough force to bend the ibeam frame then bought a peaice of railroad iron to make the frame out of.



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Tom

11-24-2002 06:13:52




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 Re: Hydraulic pump motor sizing in reply to Zira, 11-23-2002 16:42:38  
Don't know much about how to measure output on hydrolic pumps; but, common sense tells me that if you you drop to about about 50% in HP and drop about 40% in RPM the performance of the log splitter will be so bad as to be unworkable.



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Zira

11-24-2002 07:13:35




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 Re: Re: Hydraulic pump motor sizing in reply to Tom, 11-24-2002 06:13:52  
To be sure, the pump will put out less flow than with an 18 hp motor. I don't know what the previous use for this pump unit was, but it would not be adequate with the smaller motor.

On the other hand, most small log spliiters I see have 7 - 10 hp motors, 11 or 16 gpm pumps, and 4" X 24" cylinders. That makes me think that my motor and cylinder are adequate. I am just not sure if my motor will drive this particular pump, or if the flow and/or pressure will be too low.

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Greg D.

11-23-2002 17:29:49




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 Re: Hydraulic pump motor sizing in reply to Zira, 11-23-2002 16:42:38  
Rule # 1: hydraulic pumps do NOT put out any pressure, they put out flow, restrictions create pressure in the system. Therefore, should you know the gear width=W, the bore diameter in the housing for the gear=D. Then measure the total distance across both gears=L. Now the fun part. GPM @ 1800 rpm=
47 x W x [2D-L] x [ L-D] ----- 2 Figure that out and you will have the displacement of your pump. Have fun!!!!! !!!!

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