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Short of doing some electronic work, I would just get a 6v charger for your 6v battery.. unless you have 2 of them to charge. If you are feeling squirely, and have some electronics aptitude, there are a variety of things you could do, from a voltage divider, to a constant current, voltage limiter circuit., to as simple as a load resistor.
For a load resistor refer to ( E = IR ) where E is voltage, I is current, and R is ohms. Find the E and I value of your float. For instance.. this 12v float probably charges at 13.4 or 13.6 volts.... if it doesn't say, try values from 13.2 to 13.6 when you do the math to see how they work out on paper. Next you need to know the I or charge current available from the unit... if it is a float, it will probably be very small, in the milliamp range.. probably 50 to 150 ma.
Once you have your E and I values, plug them in the formula, and you will come up with R or the ohm value of the load, that the charger is expecting to see. ( E divided by I = R ). As an example, 13.4 volts (E) 150ma (I ) yeilds a load value of 89.3 ohms (R) That menas that you will have a voltage drop of 13.4 volts over the load. if you are wanting to charge a 6v battery, you can try R values of around 45 ohms. lower ohms will give you a higher charge voltage, higher ohms a lower charge voltage. You will want to have a margin above 6v though. For instance, in our formula, a load resistor of 45 ohms will have a 6.75 volt drop, leaving a charging value of 6.65... ( actual rates will probably vary as the battery charges, and may be different on copper than on paper. Probably somewhere 40 to 45 ohms.... might use a variable resistor and your vom to dial it in. Probably an easier way is a constant current, voltage limiter circuit. Most easilly accomplished with diodes. Perferable silicon or epoxy rectifiers as they have a higher forward voltage drop than germanium diodes. ( you could make a zenir diode shunt circuit.. but that is wastefull, as it shunts everything over your target voltage.... ). Anyway.. silicon diodes have a forward voltage drop of about .6volts Again, guess or look up the voltage output og the charger.. then decide what voltage you want to charge at.... 7v seems reasonable If your charger is again, at say 13.4v then you will need 10 - 11 diodes.. or 10 silicon and a germanium ( .4 voltage drop ) to equal 7 exactly... but I might just go 10 silicon and leave it like that. Or you could just go get a 6v charger! Soundguy
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