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You ask why the voltage is the same comming out of the resistor as going in. This is becasue you do not have any current flowing through the resistor. The electricity can be hard to understand but it is in some cases easily compared to fluids running through hoses or pipes. I've gotten kinda wordy here but I hope this helps. Consider having a 200' garden hose connected to a big bushing comming right out of your home's water storage tank. Visualize a gauge connected to each end of the hose, a gauge in the middle and a 1"ID ball valve on the far end of the hose. If the hose end valve is closed so that no water is flowing anywhere and your tank pressure is 50PSI, then both pressure gauges on the hose will also read 50PSI. The pressure is the same all along the hose from end to end & if you squeeze the hose you can feel that it is uniformly hard along its entire length. If you open the ball valve wide open, the pressure gauge at the end of the hose will fall to just a few pounds. That is because friction inside the hose the hose is resisting the flow of the water water through it. You still have almost 50 PSI at the tank and about half that on the gauge in the middle of the hose. If near the open ball valve you squeeze the hose a little bit, you'll feel that it's resistance to your crushing fingers is about the same as if it was empty & not connected to anything. The hose is no longer hard and ridgid near its open end. Near the tank however it is still just about as hard as it was with the valve closed. Close the valve or STOP THE FLOW and all the gauges will once again read the same pressure. The hose will again be uniformly hard. Cut the hose down to just a hundred feet and you already know that you'll get more gallons per minute than through the 200 foot hose but the gauge at the end will still read not more than just a few pounds. You'll get more water in less time but still 50 PSI at the tank & just a few at the end. Friction again reduced the pressure readings but only when the fluid is flowing through the hose. Since we have less resistance (half as much hose) and we still have a difference of roughly 50 PSI pressure, we receive more gallons each minute. If you throw the hose away and put that valve right on the tank, when you open it you'll have a tremendous flow of water per minute but still only a pressure difference of 50PSI! Less resistance, the same pressure but a lot more water per minute. In all cases it all evens out. In a good non electronic ignition circuit with points open, you do not have any current flowing so the resistor is just like the garden hose with the valve closed. The voltage at both ends of the resistor is the same. When you allow current to flow through the resistor, only then will the voltage will be different from end to end. When no current (water) flows, points open (valve closed), the voltage (water pressure) is the same throughout the system. When current (water) flows through a resistance, voltage (pressure) readings will differ thoughout the path of the circuit (length of the hose). Now that I've said all this, I can't tell you if it is working properly because there are some oddities in some ignition systems. Wico distributors for example. In particular, those on pony motors and in the X series distributors. Post back what you have and somebody can give you more information. We're guessing maybe a pony becasue of the cost of your coil? Hope this helps some. Later.
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