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Math formula

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OldsterGA

03-17-2002 10:06:48




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Showing my senility and ignorance again. Can someone give me the formula for calculating the tonnage of a log splitter (or any other) cylinder. I used to know it but have beem out of school a looooong time. Thanks.




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OldsterGA

03-18-2002 05:25:48




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 Re: math formula in reply to OldsterGA, 03-17-2002 10:06:48  
Thanks much for the information.



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Kurt

03-17-2002 16:37:43




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 Re: math formula in reply to OldsterGA, 03-17-2002 10:06:48  
FOrce = pressure X the area of the piston. For example, a 2" bore cylinder = 3.14 square inches X 2000psi = 6000+ pounds of force. to calculate piston area = to piston diameter times 2 then times .7854. Be sure to subtract the rod diameter when figuring the retraction force.



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BB

03-18-2002 10:14:49




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 Re: Re: math formula in reply to Kurt, 03-17-2002 16:37:43  
This information is correct. HOWEVER!! The working force can be considerably different. Using this example of 6000 pounds on 3.14 sq inches = 1900 pounds per sq in. On a log splitter, you are applying the force to a relatively sharp edge with very little surface area. Assume the sharp edge has .25 sq in of surface, then the working force is 1900 divided by .25 = 7600 pounds per sq in. If you were using it in a hydraulic press and the press foot was 2" x 4" (8 sq in) then the force would be 1900 divided by 8 = 237 PSI. Quite a bit of difference in applied force based on surface area. Sort of like standing on a shovel and it will go into the ground. Stand on a 2x4 and it just lays there.

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JMS/MN

03-17-2002 11:38:45




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 Re: math formula in reply to OldsterGA, 03-17-2002 10:06:48  
You need to figure the area of the face of the piston inside the cylinder, and multiply that area by the operating pressure of your hydraulic system. Area = pi x (r squared) where pi is 3.14, and r is the radius of the face of the piston. Example: using an eight inch cylinder, the radius is four inches, so Area = 3.14 multiplied by (4 x 4) equals 50.24 square inches. With a 2000psi system, that would give you 100480 pounds of push. Retraction pull would be slightly less, since you have to subtract the square inches of the piston rod (the face of the backside of the piston is reduced by the diameter of the rod)

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Hey JMS Ultradog MN

03-17-2002 12:02:02




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 Re: Re: math formula in reply to JMS/MN, 03-17-2002 11:38:45  

Could I ask you some questions about those grain drills you were talking about the other day.
That guy, William Watts, mentioned his drill had been cut down from a wider one. Wondered how hard it would be to do that to a drill if I bought one. I've never used a drill before and know nothing about them. I just want something about 6' wide.
I'm pretty handy. Have a torch and welder here and my neighbor has a metal lathe. Any idea how much work it would be to cut one down?
Email? I'm in Mpls. where are you?
Thanks

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JMS/MN

03-18-2002 07:24:31




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 Re: Re: Re: math formula in reply to Hey JMS Ultradog MN, 03-17-2002 12:02:02  
UltradogMN-I'm an hour west of you, near Hiway 55.Yes, it would be feasible to reduce the size of the drill. My Moline drills are ten feet wide, and the simplest reduction would be to make it a five footer, since each half of the drill has its own drive system. I think the middle divider is also solid steel, and the grass seeder is two five foot sections. It would be easy to split the drill, and remount the wheel in a new position, since the other wheel and drive system would stay intact to drive the drill mechanism. Also, the hitch would have to be remade, but that is minor.

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William Watts

03-27-2002 19:20:19




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 Re: Re: Re: Re: math formula in reply to JMS/MN, 03-18-2002 07:24:31  
UltradogMN and JMS-MN----Just wanted to let you know that the guy in Kansas said the machine shop charged him $600 to cut down the drill. Obviously he had to make a living too. I am also in MN (Shakopee). I plan on using the drill for grass seeding. It needs a little work. I want to change it over to hydraulic lift and the grass seed attachement box needs a drive chain. Good luck in your venture.

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OldsterGA

03-17-2002 10:07:55




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 Re: math formula in reply to OldsterGA, 03-17-2002 10:06:48  
beem should be been, I know.



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