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Re: Re: Wisconsin and Clinton engines (single cyl.)
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Posted by CRAIG on August 04, 1999 at 17:15:24 from (209.115.44.6):
In Reply to: Re: Wisconsin and Clinton engines (single cyl.) posted by CRAIG on August 03, 1999 at 20:44:27:
TO FIND HORSE POWER: MULTIPLY THE AREA OF THE CYL. BY THE LENGHT OF STROKE IN INCHES AND THE PRODUCT BY THE NUMBER OF REVOLUTIONS PER MINUTE THEN DIVIDE BY THE CONSTANT 10000 FOR 2 STROKE OR 13400 FOR 4 CYCLE. EXAMPLE:4"BORE 4"STROKE 1000 REVS. PER. MIN. CONSTANT 13400. THE 4"BORE IS, 12.56 AREA x 4 =50.24 x 1000 = 50240 DIVIDE BY 13400 = 3 3/4 HP FOR ONE CYLINDER.
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