Posted by Showcrop on November 30, 2009 at 06:33:44 from (75.67.231.80):
In Reply to: OT. Engineering Problem posted by Lost Password on November 30, 2009 at 03:28:14:
t=r x F The horse pulls with Force multiplied by the radial distance from the pivot point of the evener. Resulting in torque around the pivot point. So you "even up" unequal horses to get the equal pull by giving one some leverage against the other. But, if they are equal pullers, yes, the one with the longer side would then pull ahead of the other. That is unless the lazy yet strong horse sees the other pulling ahead and pulls harder to stay up. This is something that someone experienced in horse pulling would sometimes do to maximize his team.
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