Re: OT-Balistics question

Posted by MarkB_MI on February 13, 2009 at 03:05:28 from (216.234.123.82):

In Reply to: Re: OT-Balistics question posted by OhioD14 on February 12, 2009 at 21:25:00:

Hmm,

I also get 23 miles in a vacuum.

The kinetic energy is 1/2mv², where m equals mass of the projectile and v is the muzzle velocity.

At the apogee of its arc all kinetic energy is converted into potential energy. Potential energy is mgh, where m is mass, g is the acceleration of gravity (32 ft per second squared) and h is the elevation.

So:
mgh = 1/2mv²
h = (1/2v²)/g
h = (1/2 x 2800² ) / 32
h = 122,500 ft
h = 23.2 miles

Of course, the real height will be MUCH less. Projectiles traveling at over two times the speed of sound lose velocity very quickly. 1000 yard highpower competitors have to use fairly heavy bullets to keep them from going subsonic before they get to the target. I don't know how to do the calculations, but I would be very surprised if a typical rifle projectile would go over a mile vertically. Someone with access to a ballistics program can do the calculations, based on the ballistic coefficient of the particular bullet.

Replies:

• Re: OT-Balistics question KIP in MX 08:44:16 02/13/09 (0)

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