Re: hyd cylinder calculations

Posted by john bud on April 06, 2006 at 19:21:52 from (68.248.249.110):

In Reply to: hyd cylinder calculations posted by time to quit farm on April 06, 2006 at 19:13:16:

There are 2 measurements for cylinders. The diameter of the cylinder (bore) and the diameter of the rod.

The push force is pressure x pi r squared

So, your 2 inch cylinder has an r of 1 inch (half the diameter). I'm going to guess your pressure at 1000 psi (cuz it's easier for me!)

1000 * 3.14159 * 1*1 = 3141.6 pounds of force.

The pull force is the same, but you have to also do it for the rod and subtract that number from the 3141.6. The rod takes up space on the surface that pushes and that's why it is subtracted.

You have to do triangles to determine effective force by calculating the vertical component of the force provided by the cylinder. If you don't know what that means, then draw out a measured picture of the mounted cylinder in the retracted position and the extended position and post that here. The math will get done for you.

jb

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