Just rough calculations using these dimensions and simple area formulas and addition/subtraction, the external surface area of a tire that size is approximately 2100 square inches.
(31.7/2)^2 X pi X 2 {area of the sidewalls of the tire}
-
(16/2)^2 x pi x 2 {area of the sidewalls of the rim}
+
99.7 x 9.3 {area of the tread}
=
~2100 square inches
x
80 pounds per square inch
=
168,000 pounds of force
Based off the inside dimensions of the tire it will be a bit less, but you get the idea.
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