Re: Re: Gear Ratio Math?

Posted by Alberta Mike on January 20, 2002 at 12:40:58 from (209.47.89.122):

In Reply to: Re: Gear Ratio Math? posted by BECK on January 20, 2002 at 07:27:02:

Yup, you are correct again I would say. I thought it through again and came up with some simple shaft revolutions. The 22/47 ratio (standard) gives you the output shaft turning about 47% (or 0.47) of a turn for every single turn of the input shaft. Then the 20/45 ratio gives you only about 44% (or o.44) of a turn on the output shaft for every turn of the input shaft. So the second example above (20/45) is a lower-geared set. I THINK THAT WAS K-MO'S ORIGINAL QUESTION THAT HAD HIM SCRATCHING HIS HEAD. HE SAID THAT SECOND SET (20/44) WAS GEARED LOWER YET IT WAS CALLED THE HIGH-SPEED OPTION BY IH. That part still doesn't make sense, do you think it does?

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• Re: Re: Re: Gear Ratio Math? BECK 14:48:52 01/20/02 (0)

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