Posted by willie in mn on August 15, 2018 at 12:24:51 from (172.242.135.78):
In Reply to: Small grain bin setup posted by Dave H (MI) on August 15, 2018 at 08:01:43:
Did a little research. Had to check on my slide rule to get formula for volume of the cone, which is 1/3 Bh, , where B is the area of the circle & h is the height. Also 1 cubic foot equals 8/10 of a bushel & corn weighs 56 pounds /bushel. Now to do the work, bin is 5 ft diameter by 10 ft tall. Cone part of the bin is probably 5 ft tall estimate, close enuff. Pi times radius squared- 2.5x2.5x3.14=19.625 sq ft area of the circle. 19.625 times 5 (height of the cone) divided by 3 (per the formula) = 32.7 cu ft volume of the cone. 19.625 times 10 (height of the cylinder) = 196.25 cu ft volume of the cylinder. volume of the cone plus the cylinder = 228.9 cu ft. 228.9 times .8 =183.1 bushel. 183.1 times 56# =10256.97 pounds corn. Hope my calculations are correct. The 11000 # estimate mentioned below is close enough. Hope this helps. Will leave the concrete requirements to someone more expert in that field.
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