Posted by greygoat on January 17, 2008 at 07:54:36 from (75.121.153.192):
In Reply to: log spltter posted by andys on January 16, 2008 at 15:56:43:
If you are working a hydraulic woodsplitter from tractor hydraulics, then, speed is determined by pump output in gallons per minute, (GPM), and the machine may cycle faster as the tractor engine is speeded up. Splitting force is determined by the tractor output pressure, pounds per square inch, (PSI), which is determined by the safety relief valve setting of the tractor hydraulic system. Force is also subject to the size of the splitter cylinder. A 4 inch bore cylinder has 12.56 inch of piston area. pressure times area equals tonnage of force (12.56 X 2000 =25120) divide by 2000 lbs per ton equals 12 1/2 ton. the same 2000 psi on a 5 inch cylinder, (19.625 inch area) is 39250 lbs which is 19.62 tons. There are reducing valves which reduce pressure going from a system to a component, but no valve can increase pressure beyond that of system pressure setting. Determine system pressure, and knowing cylinder size will allow you to calculate splitting force
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