Depending on your water table you may find it easier to hammer two wells. Use one well to supply the cool water to the radiator inside your shop and the other well to the return warm water to the ground. If you have another use for the water, make up water for a pond etc. the second well would not be required.
Assuming the water enters your radiator At 50 degrees F and exits at 60 degrees F, each gallon of water can supply 83 Btu of cooling. Also, lets assume the shop air enters the radiator at 90 degrees F and exits at 70 degrees F. The 83 Btu from the water can cool 227 cubic feet of air the 20 degrees (90 to 70). NOTE, this is for dry air, humidity will reduce the performance same as for an air conditioner.
A 36' x 48' x 18' shop encloses 31,104 cubic feet of air. Using a 1 GPM pump will supply 227 cubic feet of cool air per minute and require 137 minutes for one air exchange. A 10 GPM pump could supply enough cooling for one air exchange each 13.7 minutes.
Yes it is possible....it can make a significant difference if sized corrrectly.
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Today's Featured Article - What Oil Should I Use? - by Francis Robinson. I keep seein this question pop up over and over again in discussion groups all over the web. As with many things there are often several right answers and a few wrong ones. Some purist I'm sure will disagree to no end with what I will tell you but most of us out here in the real world don't really care do we ? Some of them only bring their noses down out of the air long enough to look down them anyway. If you are like me you are only doing this old tractor stuff because you enjoy it. You
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