It requires 1 btu to heat 1 lb of water 1 degree F. 600 gallons of water weighs 5000 lbs, therefore 5000 btus are required to raise the temperature of the tank 1 degree. For example if the water comes out of your well at 50 degrees, to heat the tank to 75 degrees would require 125,000 btus (5000 x 25).
If electricity is available, 1000 watts for 1 hour is 3410 btus. A stock tank heater is typically 1500 watts and would require 24.4 hours [125,000 / (1.5 x 3410)] to heat the tank from 50 to 75 degrees. This assumes no heat loss so you would want to up size the heater (use two stock tank heaters) to account for a cold windy day. Also keeping the tank covered until use would reduce the heat loss.
If electricity is not available, propane contains approximately 90,000 btu per gallon. Assuming a heater efficiency of 70% approximately 2 gallons [125,000 / (90,000 x 0.7)] of propane are required to deliver the 125,000 btus to the water. If the propane heater is rated at 10,000 btu/hr it would require 12.5 hours (125,000 / 10,000) to heat the water to 75 degrees, again assuming no heat loss. A standard 20 lb propane cylinder contains a little less than 5 gallons of propane. Again I would keep the tank covered to prevent/minimize heat loss.
Hopefully this helps in selecting or fabricating your heater.
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