Width of cut (in inches) X ground speed (mph) divide by 100 = acres per hr.
Don't just use the width of the mower, but actual cutting width. You'll have some overlap. A 60" mower generally isn't cutting a full 60". You'll probably average around 50" to 55" of actualy cut width.
Loss of efficiency due to turns, dodging obstructions, ect....100 is max efficiency. If you estimate loss of efficiency @ 10%, divide by 110....20%, 120...and so on.
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Today's Featured Article - Talk of the Town: Removin Broken Bolts - by Staff. Another great discussion from the Tool Talk Discussion Forum. The discussion started out with the following post: " How would I remove a bolt thats broken off in a piece of metal and I want to save the treads in the metal and then put in a new bolt. "
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