the 6 volt generator will run at half the current flow at 12 volts. I would say if the power does not change the alternator would be cooler. If you increased the power needs this would change.
from answers.com
Ohm"s Law defines the relationships between voltage (E), current of charged particles (I), resistance (R) and power (P). One ohm is the resistance value through which one volt will maintain a current of one ampere. One volt of voltage moving one ampere of current is "creating" one watt of power (the so-called volt-amp). ( I ) Charged particles (usually electrons) are what flows in a wire or conductor like water flowing through a pipe. Electrons flow through a conductor from points in a circuit that are more negative to points in that circuit that are more positive (electron current, also called electron flow). This flow, or current, is measured in amperes (A). ( E ) Voltage is the difference in electrical potential between two points in a circuit. It"s the push or (electrical) pressure that moves electrons through a circuit. It is what causes current flow, and it is measured in volts (V). ( R ) Resistance is a measure of a material"s opposition to current flow. It determines how much current will flow through a component for a given voltage. Resistors are used to control voltage and current levels. A very high resistance allows a small amount of current to flow for a given voltage. A very low resistance allows a large amount of current to flow for that same voltage. Resistance is measured in ohms (upper case omega). ( P ) Power is the amount "work" being done in a circuit. It is current times the voltage level across a given portion of the circuit, and it is measured in watts (W). Here"s how it works: E = I x R (voltage equals current times resistance) P = I x E (power equals current times voltage) There are variations on the theme, and here are all the expressions of Ohm"s law: E = I x R or Voltage = current times resistance I = E / R or current = voltage divided by resistance R = E / I or resistance = voltage divided by current P = I x E or Power = current times voltage P = I2 x R or power equals current squared times resistance P = E2 / R or power equals voltage squared divided by resistance
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Today's Featured Article - Memories of an IH Super A When I was ? up to 10, I worked on my Papaw's farm in Greeneville, TN every summer. As I grew older (7), it was the thrill of my day to ride or drive on the tractor. My Papaw had a 1954 IH Super A that he bought to replace a Cub. My Papaw raised "baccer" (tobacco) and corn with the Super A, but the fondest memory was of the sawmill. He owned a small sawmill for sawing "baccer" sticks. The Super A was the powerplant. When I was old enough (7 or 8), I would get up early and be dressed to
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