The cutout relay is basically a solenoid type switch which was used on the early tractors before voltage regulators. It's function is to disconnect the generator output to the battery when the engine is not running to prevent battery discharge. In the absence of a voltage regulator, the method used to control the generator output was to restrict the ground leg of the field coil by means of the field resistor. Without lights, the generator "F" terminal is either wired directly to ground (under the mounting screw of the cutout relay) which provides the high output of about 10 amps, or it is wired to the "F" terminal of the cutout relay which in turn runs through a 2.8 ohm resistor on it's way to ground. This is the low output, around 4 amps. With lights, they simply moved the field resistor to the switch where the operator can select the output without moving any wires. The resistor has the same rating whether it is located in the cutout relay or the light switch but the physical size differs between the two. I have one from the relay which won't fit the switch because it is slightly too long. Sorry for the long answer. Geoff
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Today's Featured Article - The Day Mom Drove the 8N - by Brian Browning. My Dad was wanting to put in a garden but couldn't operate the 8N and handle the old horse drawn plow he had found and rigged up to use with the tractor. Well, he decided to go get Mom out of the house and have her drive the tractor while he walked behind the plow. You got to understand that while my Mom is a hard worker who will always help whenever she can... she had never operated farm machinery before that day. Dad got her out there, explained how the clutch was the same as in our o
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