Posted by bc on April 08, 2009 at 09:23:30 from (69.149.215.139):
In Reply to: Re: Farmall 460 coil posted by rvirgil_KS on April 08, 2009 at 07:25:35:
So it says the start circuit bypasses the resistor so the coil puts out 12v when the starter is engaged giving the engine a hotter spark during startup. Then the ignition/run circuit flows through the resistor before the coil reducing it to 6v during all day running so you don't burn out the points and a hotter spark isn't needed then.
That part I can understand. That creates questions from us dummies though that I hope can be cleared up.
However, with a 12 volt internally resisted coil, doesn't it still only have one wire going to the coil and one leaving the coil going to the distributor? And if so, then how does the internal resistor know when to kick in or not and switch from 12v to 6v? Seems like a 12v internally resisted coil would need two posts for wires coming in, one from the start circuit and one from the ignition/run circuit along with the post for the wire going out to the distributor. The 12v internally resisted coil I bought at NAPA as recommended here many times only has 2 posts, one in and one out. Thus it would seem that it can only work at one voltage which is probably 6v with the resistor.
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