Hydraulic ??

Bill in Colo · Jan 11, 2011

I have two identical grapple forks on loaders same exact cylinder on both,one has adequate grab, the other does not,neither cylinder has any leak off and have been rebuilt in the last two years. One cylinder gets 2500 psi and works well, the other gets 2100 psi and not so well.
They cylinders have a 2.5"bore and 8" stroke. How much do I need to increase the bore size to do the same work with 2100 psi as with 2500.
Thanks

oj · Jan 11, 2011

A 2.5inch bore generates 12273.25lbs of force at2500psi, 2.5/2=1.25 squared =1.5625 *3.142= 4.9093 * 2500=12273.25lbs

to equal that force, a 3inch bore cylinder generates at 2100psi, 3/2=1.5 squared =2.25 *3.142= 7.0695 * 2100= 14845.95lbs

a 2.75inch bore would be closer, but i"ve never seen one... 2.75/2= 1.375 squared= 1.8906 *3.142= 5.9403 *2100= 12474.63lbs

hope that helps...

LAA · Jan 11, 2011

By my figures a 2.5 inch bore cylinder @ 2500 psi equals around 12,300 lbs. force from the piston side, a 2.75 inch bore cylinder @ 2100 psi equals 12390 lbs of force and a 3 inch bore cylinder @ 2100 psi equals right at 14,700 lbs. of force.

LarryT · Jan 12, 2011

Silly question. Have you tried adjusting your pressure relief valve on the pump or valve body?

Hydraulic ??

Bill in Colo

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oj

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LAA

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LarryT

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