Math question

Leroy

Well-known Member
On a set of gears with a 30 tooth drive sprocket to a 15 tooth driven and you change to 33 tooth drive to a 12 tooth driven how much does it change the speed of the driven and is it slower or faster? On a John Deere 594 hay rake a 4 bar has the 33 tooth drive and 12 tooth driven. Now if I would take a good 4 bar real and set it into a 3 bar frame with bad real that would be no problem to do but the 3 bar rake has a 30 tooth drive with a 15 tooth driven how much would it change the speed of the real and to slower or faster. 59 years since I had this in school.
 
Original sprockets drive rake 2.0 X drive shaft speed.

Alternate set will drive it 2.75 X drive shaft speed.

IF I'm understanding you correctly.
 
Increasing teeth on the drive will make the shaft spin faster . Increasing on the driven - slower. Decreasing driven to smaller = faster.
 
With the 33/12 combo, the driven will be faster.

15/30=2 (1 rev drive = 2 rev driven)

12/33=2.75 (1 rev drive = 2.75 rev driven)
 

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