A QUESTION ON VOLUME

RalphWD45

Well-known Member
I have to fill a tire with CC. I asked for some help, and was told that my 12x28 tire will hold 35 gal, according to the chart. I was also advised that the proper mix would be 3.5 lb's per gallon of water. Now if my tire holds 35 gallon of liquid, and I add 3.5 lbs of CC to each gal, I would be mixing, over 122 lbs of CC to 35 gal of water. Won't that increase the gallons of liquid quite a bit past 35 gallon? I really don't see how I got past the freshman year, much less graduated!
 
Take a <a href="http://www.ehow.com/how_7447614_mix-calcium-chloride-water.html">look at this information</a>.

After following the mixing instructions of 1 gallon of water and 3.5lbs of calcium chloride, you might consider measuring the volume of water "mixed" with the dissolved calcium chloride.

Divide 35 gallons by your resulting "mixed" volume to determine how many "mixes" you need to fill the tire.
 
James Howell has the solution for you (pardon the pun). There"s a popular experiment in high school chemistry where you dissolve table salt in water and surprisingly see a decrease in volume. Don"t know if you"ll see the same results with CaCl. But the whole point is to end up with a denser liquid, so in any case the volume change will be small.
 
WOW! That site says that I will get a chemical reaction, and create heat!, and the more you stir it, the hotter it gets. That might start a meltdown, in my mixing barrel. Three mile Island revisited!
 
Ralph,
Yes, adding the calcium will increase the volume. Not by a lot, but enough to consider.
I've got a chart that shows the following numbers for a 12.4x28 tire.

35 gallons of water = 292 lbs.
30 gallons of water + 105 lbs. of CaCl2 = total 355 lbs.
28 gallons of water + 140 lbs. of CaCl2 = total 374 lbs.


I'm also curious as to what the "proper amount" of CaCl2 means.
Is someone trying to determine the freeze point with various amounts of solution. I've seen the numbers to add various amounts of CaCl2 , from 2.4 lbs. per gallon up to 6 lbs. per gallon depending on the amount of weight you want to add.

At 2.4 lbs. per Imp. Gal. the mixture remains slush free at +13° F and solid @ -23° F

At 4.2 lbs. per Imp. Gal. the mixture remains slush free @ -12° F and solid @ -52° F

At 6.0 lbs. per Imp. Gal. the mixture remains slush free @ -53° F and solid @ -62° F

1 Imp. Gal. = 1.2 U.S. Gal
 
If your figures are correct, then I can get by with less CaCl. It rarely gets colder than 20 deg , here on the coast.
 
Yup, the solution gets pretty hot when you mix it. I wait about four hours or so to let it cool down before filling the tires. I ballast with 5 lb per gallon mix.
 
(quoted from post at 20:47:01 11/19/13) If your figures are correct, then I can get by with less CaCl. It rarely gets colder than 20 deg , here on the coast.

You can get by with less but if your intention is to add weight for traction then why not add as much weight as you can in each tire.
Calcium chloride is cheaper than steel.
 

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