Early JD Conditioner

Can anyone tell me the driven roller speed,of
the early model (no1) JD Conditioner.
Thanks.

No but you can figure it out easy enough. I'm basing this answer on an IH conditioner which has the pto into a gearbox the output of which goes out at a right angle on a shaft to a drive gear. That gear drives a chain that rolls a larger upper roller and a smaller crimper roller below. I assume you are looking for a gear for the lower roller. Otherwise disregard this response.

Take a ruler and measure the diameter of both the upper and lower rollers. Measure the number of teeth on the upper roller.

Calculation example:

Upper roller diameter 10"
Lower roller diameter 8"

Upper roller gear teeth 20
Ratio of lower to upper is 0.8:1 (lower roller has to roll 1 1/4 revs to equal one rev of the top roller).

So 20 x .8 = 16 teeth for the lower roller gear.

HTH,
Mark

Brain PFART. The ratio of the diameter to the circumference is pixd. Since pi is 22/7 or 3.14, the parts of the rollers that touch will not be per the diameter ratio but that ratio with respect to pi.

I have to go to town right this minute and will return later today. If this thread is still up, I'll do the correct calculation on the gear ratio.

Sorry for the error. The longer you're retired, the more that slips your mind.

Mark

Calculating roller speed with be difficult without knowing gearbox ratio.

I don't think he wanted the actual speed, just the ratio between
the two as he only asked for one roller. As I said, he may be
wanting to replace a drive gear and wanted to get the right size.

Course the speed could be figured by counting input revs vs
output revs of the rt angle gearbox; probably 1:1 so then it's just
a matter of counting driven teeth vs drive teeth and relating to a
540 pto.

I thought about my numbers today and the initial value was
correct. Since the pi multiplier occurs in the numerator and the
denominator and this is a product (axb, not a+b) sort of thing it
cancels and it's just a matter of the roller diameter ratio
transferred to the tooth ratio.

Phew I'm getting rusty.

Mark

I worded the question wrongly in the first
place,should have said the drive roller ( When I
said driven I was reffering to the chain drive from the gearbox).
Would like to know the gearbox ratio,and drive chain ratio to the large roller.
Going by a sales brochure; Large Roller Dia 9"
(20 teeth). Small Roller Dia 4"(8 Teeth).
Thank You for Assistance.

First you know the PTO is 540. Mark a line on the input shaft coupler at the housing of the rt. angle gear box and the output shaft of the gearbox. Rotate the input shaft through one complete revolution so that the line is back where you started. If the output shaft is also back where it was, give or take a little slop, then you have a 1:1 meaning the drive gear is turning 540 rpm at engine PTO speed.

If it didn't line up, counting the turns, continue to rotate the input shaft until it does. If for example it takes 2 complete turns of the input shaft to make the output shaft marks line up then you have a 2:1 reduction box and the drive gear turns at half 540. The converse is true too. If you are only half way around on a rev of the input shaft and the output shaft marks line up you have a 1:2 and the drive gear is running at 2x 540.

Once you have calibrated your drive gear it's merely a ratio of the teeth. Since each roller of the chain touches each gear they are all locked together and it is just a matter of how many teeth went by the drive gear cal mark vs how many on the driven.

So count the teeth on each gear and you have your answer.

If the drive gear has 20 teeth then to make a rev, it has passed 20 chain links. If a driven gear has 20 teeth it will also go through 20 links to make a rev and it is running at the same speed as the drive gear.

If fewer teeth the driven gear will be running faster as it can complete a rev before the drive gear does and the speed is just the number of teeth ratio vs 540. The converse is true.

So If I have 20 teeth on the drive and the driven has 24 for example then with more teeth on the driven it will move slower so that means 20/24 x 540 = .83 x 540 = 450 rpm.

If I have 20 on the drive and the driven only has 16 then that is fewer teeth meaning it will run faster so 20/16 x 540 = 1.25 x 540 = 675 rpm.

On the two crimpers I have, both bottom rollers are smaller diameter than the the tops and have fewer gears. That's because since the distance around the smaller roller is shorter than the distance around the larger roller, it has to make more than one turn to equal one turn of the large one, hence fewer teeth.

HTH,
Mark