Force and leverage?

So I have an Oliver Super 77. It has a pretty nice OEM three point hitch on it. But the drawbar and bracket was missing. So I had a real nice Massey drawbar with a 3 inch offset. There were bolt holes at the bottom of the hitch for a bracket so I fabricated one out of angle iron and flat strap. The Massey drawbar with the offset would put height at about 12 and 18. Then I found a one inch by two inch bar about 7 feet long with a bend in it towards one end. I cut off 36 so that I could use it as a straight drawbar. Then I noticed the the bar was a bit twisted. I have a massive hydraulic press in my shop, so I put one end in the press and a good support near the other end. Then hooked up a four foot pipe wrench, put a 2 four foot long pipe on the handle of the pipe wrench. Then put a 5 bar in the pipe. With just me hanging on that the bar would not twist back straight. So I moved a few things outa the way and went for the loader. I put the bucket on the bar were I tried myself. Had to push the bar almost to the floor to get the twist out. So with that much force and that much leverage, what would the TORQUE be? I should have gotten a picture.
 
Torque is the distance from the object to the point force is applied, times the force. Ex. a 2' wrench on a pipe with 100 pounds force applied = 200 foot lbs.
 
I agree . Had a loader on my John Deere 3/4 breaker bar also an 8 foot cheater with a couple 300 pound men on the end a few times before
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