Tractor Math Question

lenray

Well-known Member
Tractor is 104 inches wide at the outside of the rear tires------SO with a snow blade on the front and set at an angle--how wide will the plow need to be so the rear tires are on cleared ground????

Set at an angle to move the snow to the side.....
 
Obviously depends on the angle of the plow blade. More angle, more length needed. Let me know the maximum angle you will use and I'll calculate the length of the plow needed.
 
just use a tape measure and measure from the width of one rear tire to the other one at the max. angle you want and you will have the length.
 
Let's see...the sum of the square root...
And how deep is the snow? Deeper snow will spill back farther, and then there is wet snow vs loose dry snow. Too many variables for me!
 
104 divided by cos of angle = width of blade.

So If you set blade at a 45 degree angle width of blade needs to be 147 inches. 30 degrees width is 120.

I hope I remeber my trig functions. Haven't used them in a long while.
scientific calculator
 
What George Marsh said. 10deg/106", 20deg/112", 30deg/120". 45deg/147" plus allow for spill back which is hard to calculate. I might be thinking 12 feet at 45deg. Dan
 
When I set my 7 ft back blade at the smallest angle, the snow is heavy, the back wheels on my Jubilee are sliding sideways.

I made an 8 ft blade for the front bucket on my backhoe. It's made with just a slight angle. My front wheels are sliding sideways in heavy snow.

Newton said for every action there is an equal and opposite reaction. You try to push all that snow in just one direction, good luck keeping your front wheels from sliding in the opposite direction.

A large V-shape design might be the way to go.
 
You can do all the math and geometry you want, but a blade is never wide enough! But you never have enough power or traction. I built a 6 foot blade for a Farmall A that I had narrowed up to a little over 4 feet, it worked OK.
 
I think cosine is the function you are looking for: blade length X cosine of the blade angle = width of the path cleared.

For a straight blade or a loader bucket, I'd use a 9 foot width (108 inches) to clear a path for a 104 inch wide tire track.
 

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