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Tool Talk Discussion Forum

Re: JohnT?

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George Marsh

12-16-2013 14:42:16

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No offense taken.

So, if I got things right in my head, with or without caps, the motor uses the same current and generates the same heat.

The only thing that benefits is the circuit breaker in the load center is seeing less amps and there is less I squared loss in the wire going to the motor.

What about a generator? Is it better for a genny to PF?


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John T

12-16-2013 15:27:35

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 Re: JohnT? in reply to George Marsh, 12-16-2013 14:42:16  
"So, if I got things right in my head, with or without caps, the motor uses the same current and generates the same heat."

I cant say that's exactly right, but its hard to explain and I'm way too lazy to dust off my books lol. Here's what I will say, however. If the PF is unity meaning, the current isn't leading or lagging the voltage, its in phase, the vector sum of the resistive current component and reactive (L/C) current component is the same as the resistive ONLY i.e. C canceled out the L. However, if the PF is less then unity, the current is the vector sum of the 2 out of phase components (R + L/C) even though a meter doesn't take that into account, its watts NOT Volt Amps.

"What about a generator? Is it better for a genny to PF?"

The utility or a genset generates a sine wave and it has to "work" less if the load is unity PF. If the PF is lousy the genset or utility is actually having to produce the in plus out of phase current components (vector sum) and that's why we were charged a penalty for a lousy PF even though our watt hour meters registered the same

HEY GEORGE IM RUNNIN OUTA SMARTS ON THIS PF STUFF this is my best recollection but certainly not warranted correct. When I believe an answer is correct I just state it, but Im NOT sure on this PF stuff, its been too long, dont take any drastic steps based on the above, consult someone more current in the trade whose not been retired over 20 years ........

Sorry, but that's all I got

John T

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George Marsh

12-16-2013 19:16:24

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 Re: JohnT? in reply to John T, 12-16-2013 15:27:35  
thanks JohnT,
I am very familar with vectors, series and parallel tank circuits, XL, Xc, R, Z, all the equations in electronics. Never really applied them to motors.

What I'm not 100% sure of, but going to take a guess an educated guess on what you call unity(powerfactor).

When the phase angle between the vector sum and R is zero, the cos of zero is one and the Power Factor is 1, unity.

So, if you were to find the phase angle then the cosine of that angle transulates to the power factor. example. The phase angle is 45 degrees, the cosine of 45 is .707. Therefore you would say the power factor is .707. As the phase angle approaches 90 degrees, the power factor approaches 0. As phase angle approaches zero, power factor approaches 1.

If you can follow this chatter, good luck.

Yes. I have too much time on my hands.

So, is the cos of phase angle = power factor.

Inverse cosine of power factor = phase angle.

I'm kinda of rusty too. Only been retired 10 years. I pitched all my books.


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John T

12-17-2013 03:45:52

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 Re: JohnT? in reply to George Marsh, 12-16-2013 19:16:24  
"So, is the cos of phase angle = power factor. "

YOU GOT IT.........And if they are in phase the angle is zero and the cosine of zero is one...

Fun huh

John T

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George Marsh

12-17-2013 06:11:34

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 Re: JohnT? in reply to John T, 12-17-2013 03:45:52  
Don't think I ever read that any place. Why do some try to make it so complicated?

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