Log Splitter CYLINDER

lenray

Well-known Member
I have a hyd. cylinder 3 FT. long 2 1/4 dia. piston and the cylinder is 4 in. in dia. it does a good job with my 756 IHC.

I want to replace it with a cyl. that is 3 ft. 3 in. long a piston that is 2 in. in dia. and the cylinder is 4 1/2 in. in dia.

A little diff. in the dimensions , but not much---what do ya think?????????
 
Only difference I can see will be the length of log you will be able to fit into the cradle, it will be 3 inches shorter.As for power of the cylinder or speed, the link below you add your numbers to the boxes and it will show you the difference in speed or power.LOU
poke here
 
Lou Has is Right. The longer cylinder will decrease the log length by 3 inches. Unless you are cutting the existing mounts and rewelding them. Another thing to think about is if the current ram and wedge or push block (depending ou your configuration) go all the way to the other end of the splitter; will the new cylinder cause things to hit when fully extended?
 
OK I see what you mean---I should have mentioned that I was moving the new cylinder back to a new mounting---I didn't explain it very well.

THANKS
 
(quoted from post at 22:10:02 11/04/12) OK I see what you mean---I should have mentioned that I was moving the new cylinder back to a new mounting---I didn't explain it very well.

THANKS
sing Lou's calculator reference, you will see that the reduction from 2.25 to 2 inch will result in a force reduction, such that you will have only about 80% of what you had before.
 
You say the new one has a 2 inch dia piston with a 4 1/2 inch cylinder. Are you measuring the rod dia as the piston and is the 4 1/2 inch the outside dia of the cylinder? If that is the case you are gaining force by a larger dia cylinder (assuming the wall thickness is the same thereby increasing the piston dia by 1/2 inch). The rod dia is 1/4 in smaller which will slow the retraction speed slightly but not noticeable on a cylinder of that size. It should work out good.
 
The size of the rod should have little or nothing to do with the force exerted by the cylinder. The size of the cylinder and the part that the fluid pushes on is the key. I do assume this is a double acting cylinder.

If you measure the ID of the cylinder and then calculate the cross sectional area. Then take the pressure of the system and you can determine the force on the rod or in math...

F= P x A or F = pressure x pi x r x r
Force on a Hydraulic Cylinder
 
I don't think you're going to gain that much by changing. If your pump is a two-stage it will split about anything you have. I quit using the fireplace and bought a stove years ago and I always cut the wood about 24-26" long. I built this splitter in 1982 and I bought the pump and control valve from Northern Hydraulics. The cylinder was off an Army vehicle called the Goer. It was steering cylinder and was sold at a gov auction. Then they moved it about 50 miles away. I bought a nice lawn trailer too. Hal
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