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Tractor Pulling Discussion Forum

Re: Calculating Approximate CFM Requirements

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the haulin harris

12-12-2012 12:53:45

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cubic inches X rpm divided by 3456

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north puller

12-12-2012 15:29:22

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 Re: Calculating Approximate CFM Requirements in reply to the haulin harris, 12-12-2012 12:53:45  
3456 is assuming that your engine is 100% efficient. However, most N/A engines are lucky to be 80% efficient (only moves 80% of the air it acually displaces) and therefore would only require 80% of the CFM. A little more accurate formula would be inches X RPM / 4320.
This post was edited by north puller at 15:33:28 12/12/12.

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12-14-2012 07:10:47

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 Re: Calculating Approximate CFM Requirements in reply to north puller, 12-12-2012 15:29:22  
Your explanation is the closest estimate to my understanding. I was curious how some folks figured it, because it sometimes seems to be an afterthought for pullers, as it was on my MM. I'm hoping for some better power from appropriate CFM and 1/8" more bore next year. X 1716 / 3456 X 80% = 173cfm

I've probably been running 130cfm at the very most.

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12-13-2012 19:58:23

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 Re: Calculating Approximate CFM Requirements in reply to north puller, 12-12-2012 15:29:22  
Quoting Removed, click Modern View to see

I think you would be surprised at the amount of air required to run these pulling engines.

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