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Ford 9N, 2N & 8N Discussion Forum
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Re: JMOR - Explain Horses and Horsepower

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Bulldozer

11-13-2012 06:52:28
24.165.92.6



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The torque an engine develops is a fuction of many variables but compression ratio of the engine is a major contributor.

Consider two engines with equal displacement, one has a compression ratio of 6.7:1 and another engine has a compression ratio of 11:1. Which engine will develop the most torque?




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Jerry/MT

11-13-2012 09:08:30
206.183.116.145



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 Re: JMOR - Explain Horses and Horsepower in reply to Bulldozer, 11-13-2012 06:52:28  
If two engines are rated at 20 hp and at the same rpm, it will produce the same torue at that rpm independent of the displacement or the compression ratio. Horsepower is horsepower.

An engine with a higher compression ratio will produce a given horsepower with less displacement than one with lower compression ratio. A large displacement low compression ratio engine can produce the same horsepower as small displacemnt high compression ratio engine. How ever if they are rated at the same horsepower and they have the same OUTPUT SHAFT RPM, THEY WILL PRODUCE THE SAME TORQUE.

Torque = HP/C X RPM!

These are facts. You can believe what you want.

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Bulldozer

11-13-2012 07:42:05
24.165.92.6



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 Re: JMOR - Explain Horses and Horsepower in reply to Bulldozer, 11-13-2012 06:52:28  
Torque ~ engine displacement, compression ratio

For example what engine develops the most torque
having equal displacement, the aircooled gasoline engine with CR = 6.7:1 or the diesel engine with CR = 22:1 ?

The engine output shaft torque is proportional to the engine compression ratio but not directly portional but enters the equation as a major contributor.



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