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Implement Alley Discussion Forum

Re: Hillbilly Boom pole

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Indiana Ken

07-11-2013 19:24:40

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For example: If we assume the 1000 Lb bales are round bales 5 ft wide then the leverage as you call it, or bending momment, would be 5 Ft / 2 x 1000 Lbs = 2500 Ft-Lbs. Since the bale is uniform we can simply treat it as a point load acting at its center or 2.5 Ft. Now if you attach a chain at the end of an 8 Ft pipe, the chain acts as a point load at 8 Ft. The load acting at 8 Ft that equals a bending moment of 2500 Ft-Lbs can be found by: 2500 Ft-Lbs = 8 Ft x Load. Solving for load we have: Load = 2500 Ft-Lbs / 8 Ft = 312.5 Lbs. Therefore, a load of 312.5 Lbs at the end of an 8 Ft pole will result in the same bending moment as a 1000 Lb bale that is 5 Ft wide. The bending moment acts to break or bend the bale spear where it is attached to it's mount. Or, to state the same thing another way: a load at 8 Ft has 3.2 times the leaverage as a bale which acts at 2.5 Ft.

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07-12-2013 05:26:34

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 Re: Hillbilly Boom pole in reply to Indiana Ken, 07-11-2013 19:24:40  
Nice calcs. I help to relieve the tension on the end of the spike by doing what I said. I welded a plate at the base of the spike to the frame, that the pole just slides under....sliding fit. That way the bending moment of the pole comes into play in distributing the load. Plus with a simple bolt dropped through the two, it is locked in place and installation/removal is fast.

I found that a 2 7/8 drill pipe works best having enough metal thickness (schedule number) and diameter. plus it's not too heavy to lift.


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