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| Implement Alley Discussion Forum |
Topic: Re: How to measure the width of a disk
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| JD Seller
01-02-2013 21:02:14
208.126.196.144
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That is easy to tell. The width of the back IS NOT the cutting width. Every JD sales guide explained how to tell the width of a disk. Here it is:You count the number of blades on the front gang. Multiply that times the disk blade spacing. Then add the disk blade spacing one more time. That is the true cutting width. So a 18 blade disk with a 7 inch spacing would be 18 x 7 = 126 inches Plus 7 = 133 inches 133 divided by 12 = 11.08 so it would be called an 11 foot disk. |
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| Indiana Ken
01-03-2013 09:29:46
66.249.232.131
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Re: How to measure the width of a disk in reply to JD Seller, 01-02-2013 21:02:14
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| Quoting Removed, click Modern View to see
I think you meant to say, count the number of blades on both front gangs. However, I am still confused:
Two gangs at 9 blades each would have 18 blades but only 16 spaces; resulting in 112". Adding another 7" results in 119" or about 10 feet. This formula does not account for any space between the two gangs however that is probably a moot point. My confusion is more concerning the logic of the method. |
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| Tx Jim
01-03-2013 10:17:55
67.142.163.24
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Re: How to measure the width of a disk in reply to Indiana Ken, 01-03-2013 09:29:46
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| This is from footnotes in the parts catalog for a JD 210 disk harrow
Last number for each is number of disk
(A) TOTAL QUANTITY FOR 3.5 M (11'4") SIZE IS 40.
(A) TOTAL QUQNTITY FOR 3.8 M (12'7") SIZE IS 44.
(A) TOTAL QUANTITY FOR 4.2 M (13'9") SIZE IS 48.
This is spacer between disk
AN183748 SPOOL, PLAIN-WELDED (7 1/4") |
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| Leroy
01-03-2013 07:01:56
69.88.205.38
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Re: How to measure the width of a disk in reply to JD Seller, 01-02-2013 21:02:14
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| That is NOT the way it is in my JD operators manuals. |
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